Let D be the midpoint of the side BC of the triangle ABC

Verify that:
$$\vec{AD}=\tfrac12\big(\vec{AB}+\vec{AC}\big)$$
Let D be the midpoint of the side BC of the triangle ABC

Verify that:
$$\vec{AD}=\tfrac12\big(\vec{AB}+\vec{AC}\big)$$
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$\vec {AD}$
$=\vec {AB}+\vec {BD}$
$=\vec {AB}+\frac12 \vec {BC}$
$=\vec {AB} +\frac12 (\vec {AC}-\vec {AB})$
$=\frac12 (\vec {AB}+\vec {AC})$