Vitali convergence and convergence in measure

Question

Part of the general Vitali's Convergence theorem says:

Let $\{f_n\}$ be a sequence of functions on $E$ that is uniformly integrable and tight over E. If $\{f_n\} \rightarrow f$ pointwise a.e. on $E$, then $f$ is integrable over $E$.

Now, can $\{f_n\} \rightarrow f$ pointwise a.e. be removed and replaced with $\{f_n\} \rightarrow f$ in measure?

Thank you.

Answer 1

Yes, convergence in measure implies a.e. convergence along a subsequence.