Volume between $z = 3\sqrt{x^{2} + y^{2}}$ and $x^{2} + (y-1)^{2} = 1$ and $z = 0$

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Find the volume between $z = 3\sqrt{x^{2} + y^{2}}$ and $x^{2} + (y-1)^{2} = 1$ and $z = 0$

I am not sure how to approach finding the limits of integration. Would I need to change coordinate systems?

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Hint: what is the projection of the solid in the $xy$ plane? Let $D$ be this zone.

Once you have determined $D$, ask yourself, how does $z$ vary over $D$.