Volume bounded by the surface $x=-1,\;x=1,\;y=-1,\; y=1, \; z=2,\; y^2+z^2=2$

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Volume bounded by the surface $x=-1,\;x=1,\;y=-1,\; y=1, \; z=2,\; y^2+z^2=2$ in $R^3$

The region $z=2 $ and $y^2+z^2=2$ is confusing me. I know this is a cylinder with axis parallel to $x-axis$ and bounded above and below by $x=1$and $x=-1$ respectively. We take the projection in the $y-z$ plane.

I set up the following integral for this volume :

$$\int_{y=-1}^{1}\int_{z=\sqrt{2-y^2}}^{z=2} \int_{x=-1}^{x=1}dxdzdy$$. Is this correctly set up?