Can somebody help me get started in the right direction for this question involving volume? The question is "Find the volume of the solid region inside the hemisphere $x^2 + y^2 + z^2 =6, z<0$ but outside the cone $z = -\sqrt{x^2 + y^2}$. I converted it into polar co-ordinates, but I'm not sure if I'm on the right track when trying to determine the bounds.
2026-03-29 12:31:47.1774787507
Volume bounded by two solids
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You can use $\displaystyle V=\int_0^{2\pi}\int_{\frac{\pi}{2}}^{\frac{3\pi}{4}}\int_0^{\sqrt{6}}\rho^2\sin\phi\; d\rho\; d\phi\; d\theta$