Compute the volume of the solid of revolution that results from revolving $f(x)=\cos(x)$ between $x=-\pi/2$ and $x=\pi/2$ around $y=-1$. I know how to do so around the $x$-axis or the $y$-axis, however, I am not sure what to do in this case.
2026-03-25 01:17:23.1774401443
Volume of solid of revolution ($\cos(x)$)
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If you draw the graph, you can see that it is the same volume as revolving $ f(x) = cos(x) + 1$ around the x-axis. You just translate the whole thing up with 1.