waht does $dW^1dW^2=\rho dt$ exactly mean

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I have a very simple question about a notation:

$$dW^1dW^2 = \rho dt\tag{1}$$

where $W^1, W^2$ are BM. Usually this is translated to "correlated Brownian motion". So my first question:

1. Is $(1)$ a short notation for $E[W^1W^2]=\rho t$?

Moreover, why does it follow that $d\langle W^1, W^2\rangle = \rho dt$? The bracket process attains a version which is the quadratic variation, so different from correlation. It would be appreciated if someone could clarify these different notation usually seen in Quantitative Finance papers. Many thanks

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My bet would be that the definition is in fact through the quadratic covariation: $\langle w_t,\bar w_t\rangle = \rho t$ for all $t$. Then, as a result from Ito lemma you get: $$ \mathrm dw_t\bar w_t = w_t\mathrm d\bar w_t + \bar w_t\mathrm dw_t + \mathrm d\langle w_t,\bar w_t\rangle $$ which gives you that $\Bbb Ew_t\bar w_t = \rho t$. I am not sure whether it works the other way around. Personally, whenever I read such assumption, I think of it as $\bar w_t = \rho w_t + \sqrt{1 - \rho^2}b_t$ where $b$ is a Brownian motion independent from $w$.