There is a popular result, which proves, that strong convergence in $L^2(0,T;V)$ implies strong convergence almost everywhere in $[0,T]$.
Is there an analoguous result for weak convergence? Thanks, FFoDWindow
2026-03-26 02:58:32.1774493912
Weak convergence in $L^2(0,T;V)$ implies weak convergence a.e.
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