Ok, so these questions just popped into my head and I can't seem to figure it out:
Ramsey's theorem tells us that for any $n,r\in\omega$ and any $f:[\omega]^{n}\rightarrow r$, exists an infinite set $S\subseteq\omega$ for which $f| [S]^{n}$ is constant.
A cardinal $\kappa$ is said to be Ramsey if for every $f:[\kappa]^{<\omega}\rightarrow \{0,1\}$ exists some set $S\subseteq\kappa$ of cardinality $\kappa$ such that $f|[S]^{<\omega}$ is constant.
ZFC can not prove the existence of a Ramsey cardinal (as it is quite large), but the amazing thing is that the difference in conditions seems to be minor, yet to the question: "How much must we enlarge our cardinal $\omega$ to satisfy the improved condition", we must answer: "Unprovably much".
So, several questions arise on some conditions in-between. In order to ask them compactly, I will define the following:
Definition: A cardinal $\lambda$ will be called K-Ramsey for some $K\subseteq\omega$ if for every $f:[\lambda]^{K}\rightarrow\{0,1\}$ (meaning the set of all subsets of $\lambda$ with a cardinality in the set K), exists some $S\subseteq\lambda$ of cardinality $\lambda$ which is homogeneous for f.
For the questions:
Which cardinal $\kappa$ that have been proved to exist in ZFC:
Is K-Ramsey for $K=\{m,n\}$, with $m>n\geq2$?
Is K-Ramsey for every set K of cardinality 2?
Is K-Ramsey for all finite sets $K\subseteq\omega$ that include every natural number up to their maximum (meaning every set of the form $\{1,2,...,n\}$)?
Is K-Ramsey for every finite set $K\subseteq\omega$?
For every $f:[\kappa]^{<\omega}\rightarrow\{0,1\}$ exists some infinite set $K\subseteq\omega$ and some $S\subseteq\kappa$ of cardinality $\kappa$, such that the set $[S]^{K}$ is monochromatic?
Does a cardinal being K-Ramsey for some infinite set $K\subseteq\omega$ imply it is Ramsey?
I am pretty sure a few of those finite questions can be answered using the pigeonhole principle countably many more times, but am not sure how to continue. If you have any leads or ideas or perhaps these results are well-known, please share them with me.
Even for the simplest nontrivial situation $K=\{2\}$ - let alone $2$-element $K$s - we're forced to leave ZFC:
In fact, a cardinal satisfying Ramsey's theorem for pairs (= your "$\{2\}$-Ramsey") is called weakly compact, and this is a significant large cardinal property. So the pigeonhole principle is actually extremely limited in the uncountable setting! (Or perhaps more accurately, "simple" combinatorial facts about $\omega$ secretly depend on more than just the pigeonhole principle.)