First of all: I am aware of the thread Weierstrass approximation does not hold on the entire Real Line.
My question is just that if we have a function like $sin(x)$ that can be approximated by its Taylor series, then the converge of the partial sums(which are polynomials basically) is uniform. Therefore, since $sin$ is no polynomial, I do not understand where I am wrong.
Weierstrass approximation does not hold on the entire Real Line
The question has been answered in comments: a power series $\sum_{n=0}^\infty a_n x^n$ converges uniformly on $\mathbb R$ if and only if there is $N$ such that $a_n=0$ for all $n>N$.
In this context it is natural to mention a theorem due to Carleman (1927): For every continuous function $f:\mathbb R\to\mathbb C$ and for every continuous positive function $\epsilon: \mathbb R\to (0,\infty)$ there exists an entire function $g:\mathbb C\to\mathbb C$ such that $$|f(x)-g(x)|<\epsilon (x) \quad \text{for all } \ x\in\mathbb R$$
As a special case (taking $\epsilon(x)\equiv \epsilon$) we find that every continuous function is a uniform limit of entire functions. But the theorem also allows for $\epsilon$ to decay to zero as a function of $x$, as fast as you want.
Of course, Carleman's theorem does not say anything new about $\sin x$, since it is itself entire.
For more on approximation on unbounded subsets of $\mathbb C$, see Lectures on complex approximation by D. Gaier.