Weierstrass' M-test in reverse

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Weierstrass' M-test says that the series of functions on some set $X$:

$$\sum_{n=1}^\infty f_n(x)$$

if $\forall n \in \mathbb{N}, \exists M_n$, \forall x\in X where $M_n \geq |f_n(x)|$, so the majorant series $\sum_{n=1}^\infty M_n$ converges, then the original series converges uniformly and absolutely for any $x\in X$.

But is the reverse true?

That is:

If I can prove that for some specific sequence of functions, any sequence of $M_n$ with $M_n\geq |f_n(x)|$, will have a divergent series $\sum_{n=1}^\infty M_n$.

Does that prove that the original sum is not uniformly convergent? can you give any counterexamples?

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No, that will not prove that the original sum is not uniformly convergent. For instance, let $f_n(x)=\frac1n\chi_{[n,n+1)}$. Then $\sum_{n=1}^\infty f_n$ converges uniformly to $f\colon\Bbb R\longrightarrow\Bbb R$ defined by$$f(x)=\begin{cases}0&\text{ if }x<1\\1&\text{ if }x\in[1,2)\\\frac12&\text{ if }x\in[2,3)\\\vdots\end{cases}$$But $\sup f_n=\frac1n$ and $\sum_{n=1}^\infty\frac1n$ diverges. So, if, for each $n$, $M_n\geqslant\sup f_n$, the series $\sum_{n=1}^\infty M_n$ diverges too.