Weird conformal map problem

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Construct a conformal map from the region $\omega$ = open disk of radius 1 centered at 0 minus the closed disk of radius 0.5 centered at 0.5 to $\mathbb{D}$ = disk radius 1 centered at 0.

I really have no clue where to begin. I am alright at standard conformal map examples, but this one is hard. Some help would be awesome.

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(The deleted answer seemed basically fine, but, now that it's deleted, maybe there is reason to add something...) As in the comments, it is reasonable to think of lines-and-circles together, so the crescent-shaped region is a "generalized polygon" with just two (curvy) sides. It is not a generic bi-gon, because the two vertices are the same point. If the two vertices had been distinct, mapping one to $0$ and the other to $\infty$ by a linear fractional transformation, and then applying a suitable power map $z\to z^r$, converts any such to a half-plane, and then a disk by a Cayley transform. In contrast, in your special case, mapping the single vertex to $\infty$ by a linear fractional transformation gives you a strip (bounded by two parallel lines, thus intersecting just at $\infty$).

(As in the deleted answer), a suitable exponentiation maps a (bounded, open) strip to a half-plane, and then by Cayley to an open disk.