I often see (in the case of ODE) : Let $\dot x=f(x)+\varepsilon g(x)$ and ODE. We make the ansatz that $x(t)=Ae^{\frac{g(x)}{\varepsilon }}.$ What does it mean ? In wikipedia is not well explained. Does it mean that "we suppose that $x(t)=Ae^{\frac{g(x)}{\varepsilon }}$" ? If yes, why can we suppose that ?
2026-04-02 19:42:03.1775158923
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What ansatz means?
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The Wikipedia article describes an ansatz as "an educated guess that is verified later by its results". I think that this is quite a good description.
Often we know that a solution must have a certain form. Perhaps you have learnt some rules about how to assert particular solutions of nonhomogeneous first order differential equations, e.g. for $y''(x) + 2 y'(x) + 3 y(x) = x^3$ assert $y_p(x) = a x^3 + b x^2 + c x + d$ and determine $a,b,c,d$. This can be considered to be an ansatz.
In other cases we think that a solution probably can be written on a certain form, for example like $y(x) = f(x) e^x$, and that such an assertion will make solving the equation easier. This is another form of ansatz.
"Ansatz" is German but is also used in English. It translates to "approach". So basically you make the approach $x(t)=Ae^{\frac{g(x)}{\varepsilon}}$ and then show that this choice of $x$ does indeed solve your ODE.