A smooth complex projective variety is the zero-locus, inside some $\mathbb{CP}^n$, of some family of homogeneous polynomials in $n+1$ variables satisfying a certain number of conditions that I won't spell out. It is in particular a differentiable manifold. A parallelizable manifold is a (differentiable) manifold with a trivial tangent bundle, i.e. $TM \cong M \times \mathbb{R}^n$ (equivalently, a manifold of dimension $n$ is parallelizable if it admits $n$ vector fields that are everywhere linearly independent).
Being a projective variety is an algebro-geometric condition, whereas being parallelizable is more of a algebro-topological condition. I'd like to know how the two interact. For example, according to Wikipedia, some complex tori are projective. But like all Lie groups, a complex torus is parallelizable.
What are other examples of smooth complex projective varieties that are parallelizable?
At Najib Idrissi's request, here is an answer to a different question:
Reference:
Wang, Hsien-Chung. Complex parallisable manifolds. Proc. Amer. Math. Soc. 5 (1954), 771–776.
Edit: OK, here's a way to get a family of examples containing those given by Michael Albanese.
Proof: $C$ embeds in $\mathbf R^3$, so (e.g. thinking about an outward unit normal vector) we see that the tangent bundle of $C$ is trivialised by adding one copy of the trivial bundle over $C$: $$TC \oplus \mathbf R_C = \mathbf R^3_C.$$ Now the tangent bundle of $M \times C$ is $\pi_1^* TM \oplus \pi_2^* TC$, which by hypothesis is $$\pi_1^* \mathbf R_M^d \oplus \pi_2^* TC = \mathbf R_{M\times C}^{d-1} \oplus \pi_2^* (T_C \oplus \mathbf R_C) = \mathbf R_{M\times C}^{d+2}. \quad \square$$
Proof of Corollary: As the OP remarked, $A$ is parallelisable. Now apply the Proposition $n$ times. $\square$