What are some weak conditions we can put on $f \in L^1$ so that the Fourier transform of $f$ is in $L^1$?

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I know that if $f \in L^{\infty}$ then its Fourier transform is in $L^1$. I am curious if there are some other known weak conditions one may ask of $f$ to ensure that its Fourier transform is in $L^1$.

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If we're talking about the Fourier transform on the line, the simplest thing I can think of is $f,f'\in L^2$.

Note: If $f,\hat f\in L^1$ then there is a continuous function $g$ with $f=g$ almost everywhere; this should make it clear that $f\in L^\infty\cap L^1$ does not imply $\hat f\in L^1$.