I have this region: $S={(x,y,z) \in \mathbb{R}^3: x^2+y^2+z^2\leq 1 \wedge z^2\geq3(x^2+y^2) \wedge z \geq 0} \nonumber$
I need to determine the volume but I don't know which cone should I choose.
Half of full cone?
I have this region: $S={(x,y,z) \in \mathbb{R}^3: x^2+y^2+z^2\leq 1 \wedge z^2\geq3(x^2+y^2) \wedge z \geq 0} \nonumber$
I need to determine the volume but I don't know which cone should I choose.
Half of full cone?
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What you have sketched is correct. Cone has $ 30^0$ semi- vertical angle.
Next the radius, height, are $1/2, \sqrt 3/2$ respy:
$$ V = \pi \frac13 (\sqrt 3/2) {(\frac 12)}^2 $$