what does the definite integral of a parametrised integral look like?

32 Views Asked by At

Say we have an integral $\tfrac{1}{2\pi i}\int_{\gamma}\tfrac{1}{z-a}dz$

I know this can be parametrised as

$$\tfrac{1}{2\pi i}\int^1_0\tfrac{\gamma'(t)}{\gamma(t)-a}dt$$.

My question :

So long as $a\notin \{\gamma\}$ is it true that

$$\tfrac{1}{2\pi i}\int^1_0\tfrac{\gamma'(t)}{\gamma(t)-a}dt=\tfrac{1}{2\pi i}[F(1)-F(0)]$$(as the integrand is holomorphic)

and also what doesthe expression for F(1) look like ?