Context:
Show or disprove $f[\cap\chi]=\cap\{f[X]:X\in\chi\}$ for all $\chi\subseteq\mathcal{P}(A)$ with $\chi\neq\emptyset$
I don't know how to start because I don't know what the cornered brackets mean ín settheory.
Would be nice if somebody could give me a hint how to approach this excercise.
f[A] = { f(x) : x in A }.
f[A] can also be written as f(A).
f[A] is the more precise notation.