I am reading real analysis book and encountered this symbol $\wedge$ and $\vee.$
The author says following:
- $f\wedge g=\frac{1}{2}(f+g- |f-g|)$,
- $f\vee g=\frac{1}{2}(f+g+|f-g|)$.
What are the meanings of $\wedge$ and $\vee$? For example, I want to know what $f\wedge g$ means like $f^{+}$ means the positive part of the function.
Edit: he also asserts that $\chi_{A\cap B}=\chi_A\wedge \chi_B$ and $\chi_{A\cup B}=\chi_A\vee\chi_B.$
Let $f(x)$ and $g(x)$ be functions with domain $X\subseteq \mathbb R$.
Define a new function $h=f\wedge g$ by $h(x)=\frac12(f(x)+g(x)-|f(x)-g(x)|)$ for all $x\in X$.
At each $x$, $h(x)$ is the minimum of $f(x)$ and $g(x)$,
because if $f(x)\ge g(x)$ then $|f(x)-g(x)|=f(x)-g(x),$
so $h(x)=\frac{1}{2}(f(x)+g(x)-(f(x)-g(x)))=g(x)$,
whereas for $x$ such that $f(x)\lt g(x),\;$ $|f(x)-g(x)|=g(x)-f(x),$
so $h(x)=\frac12(f(x)+g(x)-(g(x)-f(x)))=f(x)$.
A similar argument shows that $f\vee g$ is the maximum of $f$ and $g$.