Does the above mean:
- $x$ is in $X$ but [$x$ is not in $Y$ or $x$ is not in $Z$]
OR
- $x$ is in $X$ but [$x$ is not in $Y$ and $x$ is not in $Z$]
?
Does the above mean:
OR
?
On
When in doubt, simplify.
Let's give the set $Y \cup Z$ a name; I'll call it $S$, just to pick some arbitrary letter. The set $X - (Y \cup Z)$ is then equal to $X - S$. Thus, an element $a$ is in $X - S$ if and only if $a$ is in $X$ and $a$ is not in $S$.
Meanwhile, given that $S$ is the union of $Y$ and $Z$, $a$ is in $S$ if and only if $a$ is in $Y$ or $a$ is in $Z$.
Putting these together, we can see that $a$ is in $X - (Y \cup Z)$ (which is the same as $X - S$) if and only if $a$ is in $X$ and not ($a$ is in $Y$ or $a$ is in $Z$). Or, in more compact notation: $$\begin{aligned} a \in X - (Y \cup Z) &\iff a \in X - S \\ &\iff a \in X \land \lnot (a \in S) \\ &\iff a \in X \land \lnot (a \in Y \lor a \in Z). \end{aligned}$$
Note that, while this is the simple answer to your question, there are also other correct answers. For example, if you like, you can apply De Morgan's law $\lnot (P \lor Q) \iff \lnot P \land \lnot Q$ to the answer above to convert the subexpression $\lnot (a \in Y \lor a \in Z)$ into the equivalent form $\lnot (a \in Y) \land \lnot (a \in Z)$, written more compactly as $a \notin Y \land a \notin Z$, giving $$a \in X - (Y \cup Z) \iff a \in X \land a \notin Y \land a \notin Z$$ or, using English words instead of logical symbols, "$a$ is in $X - (Y \cup Z)$ if and only if $a$ is in $X$ and $a$ is not in $Y$ and $a$ is not in $Z$."
Recall that
$\cup$ is the set-theoretic counterpart of the logical operator $\vee$ (OR)
$\cap$ is the set-theoretic counterpart of the logical operator $\wedge$ (AND)
You can also use this identity $ A-B =A\cap B^C $ which just spells out the meaning of the set difference ( to be in the first one AND not in the second one) and De Morgan's identity to translate it to intersection, unions and complements:
$E:=X-(Y \cup Z)=X \cap(Y \cup Z)^C=X \cap (Y^C \cap Z^C)=X\cap Y^C \cap Z^C$
so $x \in E$ means $x $is in $X$ but not in $Y $ and not in $ Z $