I'm having trouble understanding the motivation behind a coset. The book I'm using (A Book of Abstract Algebra) states:
Let G be a group, and H a subgroup of G. For any element a in G, the symbol
aH
denotes the set of all products ah, as a remains fixed and h ranges over H. aH is called the left coset of H in G.
It goes on to say the same about right cosets. I understand this definition (or I think I do), but what does this accomplish? Is it saying that given a subgroup H, you can generate a group G using cosets?
Thank you in advance.
It is crucial to be comfortable with equivalence relations for this subject to make sense. Remember that an equivalence relation $\sim$ on a set $X$ is a relation satisfying three properties: reflexivity, symmetry, and transitivity. But the real reason why such a relation is interesting is that it is equivalent to a partition of $X$. A partition of $X$ is a collection of non-empty subsets of $X$ such that every element of $X$ belongs to exactly one of those subsets. The bijection between equivalence relations $\sim$ and partitions is given by $$a \sim b \iff a \text{ and } b \text{ are in the same subset}.$$ Here are some examples on finite sets:
As you can see, the last three examples exhibit a symmetry in their partition, and their equivalence relations take a very specific form. This is typical of group quotients. If you have a subgroup $H$ of some group $G$, the cosets $gH$ partition $G$, and each coset has the same size. Moreover, if $G$ is finite, the order of each coset has to divide the order of $G$ (Lagrange theorem). The corresponding equivalence relation is given by $$g \sim h \iff g \text{ and } h \text{ are in the same coset} \iff gh^{-1} \in H.$$
The last three examples above are merely instances of this phenomenon for the finite groups $G = \mathbb{Z}/4,\mathbb{Z}/6,\mathbb{Z}/6$ and their subgroups $H = \{0,2\},\{0,3\},\{0,2,4\}$.