I am little bit confused for manipulating bigger maths, So i am asking a simpler version. According to BODMAS we do first addition then Subtraction.
a-b+c = (a - (b+c)) or (a+(-b+c)) ?
I am little bit confused for manipulating bigger maths, So i am asking a simpler version. According to BODMAS we do first addition then Subtraction.
a-b+c = (a - (b+c)) or (a+(-b+c)) ?
When you have an expression like 2-2+2, it does not matter which order you place the terms, the answer is always the same- 2.
In your algebraic situation however, what you need to realize is that negative signs distribute. In other words:
$a-(b+c) = a+ (-1)(b+c) = a-b-c$
Which is not equal to a-b+c.
Your second expression is in fact correct, because positive signs do not distribute. (Strictly speaking they 'absorb,' as it were other signs.)
So,
$a-b+c=a+(-b+c)$
There are some fun analogies for associativity, commutativity, etc. as well, but perhaps those are for another post.