Intuitively I did: $$2\sum^2_{i=1}\sum^2_{j>i}a_{ij}x_ix_j=2(a_{12}x_1x_2)+2(a_{22}x_2x_2)$$
But I'm not sure, since I'm new to calculus.
Intuitively I did: $$2\sum^2_{i=1}\sum^2_{j>i}a_{ij}x_ix_j=2(a_{12}x_1x_2)+2(a_{22}x_2x_2)$$
But I'm not sure, since I'm new to calculus.
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There shouldn't be a second term, as the inner sum requires $j>i$ so $a_{22}x_2x_2$ is impossible. Unless, you meant $j\geq i$.