What is a set with a function $f$ that don't satisfy peano's axioms?

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I'm reading "classic set theory for guided independent study", and i'm studying the construction of natural numbers using peano's axioms.

The three axioms they give me are: A Peano system is a set $X$ with a special element $0∈X$ and a funtion $S:X→X$ such that the following also hold:

  1. The function S is one-one
  2. For all $x∈X$, $0≠S(x)$
  3. For all subset $A⊆X$, if A contains $0$ and contains $S(x)$ whenever $x∈A$, then $A$ is all of $X$.

I can't come up with any set and function that doesn't satisfy them, you guys have any idea?

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Satisfying 1 and 2: $X=\Bbb N_0$, $S(x)=x+2$

Satisfying 1 and 3: $X=\{0,1\}$, $S(x)=1-x$

Satisfying 2 and 3: $X=\{0,1\}$, $S(x)=1$