I am reading a book about approximation algorithms. The book first defines an independent system and an independent set of a family of subsets. The definition about the independent subset of a set confuses me. That is,
"For any $F\subseteq E$, a set $I\subseteq F$ is called a maximal independent subset of $F$ if no independent subset of $F$ contains $I$ as a proper subset."
So, what is the independent subset of $F$? Can someone shows me an example?
Thanks very much!
As stated in the comments, your question is about the definition of independent sets. The definition of an independent system in your book is given as:
I believe this definition has a typo in it, or at the very least it is ambiguous. I think it should read (based on the definition of independent subsets of matroids and this article about independence systems):
or equivalently,
So $\mathcal I$ does not much more than putting a "label" on each subset of $E$, marking the difference between independent sets and non-independent sets.
So, if we have a subset $F\subseteq E$, we could ask which subsets of $F$ are independent. A maximally independent subset of $F$ is a subset $I\subseteq F$ such that $I\in \mathcal I$ (i.e. $I$ is independent) and such that no $I'\in\mathcal I$ exists with $I'\subseteq F$ for which $I\subsetneq I'$.
As an example, let: \begin{align} E&=\{1,2,3,4,5\}\\ \mathcal I&=\{\{1,2,3\},\{1,2,4\},\{1,2\},\{1,3\},\{1,4\},\{2,3\},\{2,4\},\{1\},\{2\},\{3\},\{4\},\varnothing\}.\end{align} You can check that $(E,\mathcal I)$ is an independent system. As an example, $\{1,2\}$ is an independent subset of $E$, since $\{1,2\}\in \mathcal I$.
Now let $F=\{2,3,4\}\subseteq E$, then $\{2,3\}$ is a maximally independent subset of $F$. It is independent because $\{2,3\}\in \mathcal I$, and it is maximal, since if we add any other element of $F$ to $\{2,3\}$, it won't be independent anymore: the only candidate is $4$, and $\{2,3,4\}\notin\mathcal I$, thus $\{2,3,4\}$ is not independent.
On the other hand, the set $\{3\}$ is an independent subset of $F$, but not maximally independent, since $\{2\}$ is a proper subset of the independent set $\{2,3\}\subseteq F$
Note that there can be multiple maximally independent subsets of $F$. In this example $\{2,4\}$ is maximally independent as well.