What is $\lim_{q_1\to\infty}\frac{q_2^2}{ln(q_2^2)-1}\prod_{p=5}^{q_1}\frac{p-2}{p-1}$?

Question

q2 is the prime following q1. First part goes to infinity and second part to zero of course. I expect the product to go to infinity, but like to find the proof.

What is $$\lim_{q_1\to\infty}\frac{q_2^2}{ln(q_2^2)-1}\prod_{p=5}^{q_1}\frac{p-2}{p-1}$$