I am reading an old paper dated back in 70', where I encounter this $$\mid\text{det}(A,G)\mid=(\text{det}\{(A,G)'(A,G)\})^{\frac{1}{2}}.$$
We compute the determinant of a single matrix, don't we? What doest it mean by $\mid\text{det}(A,G)\mid$?
I am reading an old paper dated back in 70', where I encounter this $$\mid\text{det}(A,G)\mid=(\text{det}\{(A,G)'(A,G)\})^{\frac{1}{2}}.$$
We compute the determinant of a single matrix, don't we? What doest it mean by $\mid\text{det}(A,G)\mid$?
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Based on the dimensions of $A$ and $G$ (as defined in the paper), it appears that $\det(A,G)$ is the determinant of the matrix you get by augmenting $A$ by $G$. The identity you mention would be written as $$\left|\det(M)\right| = \sqrt{\det (M^\top M)}$$ in modern notation.