I have searched everywhere but can't find an answer. What is "O" refers to in this equation?
$${\frac {1}{2}}\log _{2}\left(2\pi enp(1-p)\right)+O\left({\frac {1}{n}}\right)$$
I have searched everywhere but can't find an answer. What is "O" refers to in this equation?
$${\frac {1}{2}}\log _{2}\left(2\pi enp(1-p)\right)+O\left({\frac {1}{n}}\right)$$
It is the "big Oh" notation described in this wikipedia article. In your case it means an approximation error of size no worse then $\pm C/n$, for some unstated constant $C$.
More precisely, such an estimate holds for all sufficiently large $n$. Your example is derived from Stirling's approximation to $\log n!$; this approximation has only limited accuracy for small $n$ but better and better accuracy for big $n$.