I know what curvature is; positive curvature, negative curvature, zero curvature, i understand. BUT THEN.. Signed curvature? I just can't seem to find something that distinguishes enough difference between what I already know and what I'm trying to find out...
From what I am seeing online signed curvature is equal to curvature which is the norm/modulus/magnitude of the differential of tangent... so what is with the name..

A "static" circle of radius $R>0$ in the plane or in ${\mathbb R}^n$ has (unsigned) curvature ${1\over R}>0$. If, however, a circle, or any curve for that matter, in the plane is traversed in increasing time in a certain direction, and if counterclockwise rotation is considered positive, then it makes sense to talk about signed curvature of this curve.
In this regard, let $$\gamma:\qquad t\mapsto\bigl(x(t),y(t)\bigr)$$ be a $C^2$ parametrization of $ \gamma$ with $\bigl(\dot x(t),\dot y(t)\bigr)\ne(0,0)$ for all $t$. Then
$$\theta(t):={\rm arg}\bigl(\dot x(t),\dot y(t)\bigr)\ ,$$ i.e., the polar angle mod $2\pi$ of the tangent vector of $\gamma$, is defined for all $t$. The quantity$$\kappa:= {d\theta\over ds}={\ddot y\dot x-\ddot x\dot y\over(\dot x^2+\dot y^2)^{3/2}}$$ is then the signed curvature of $\gamma$. This $\kappa$ is positive if the tangent vector turns counterclockwise with increasing $t$, and negative otherwise.