I was given a question which I think was incomplete.I want your opinion-
Find the area of the figure bounded by $x-3=0,y-5=0,x+3=0,y+5=0$.
My attempt- $x=3,x=-3,y=5,y=-5$ represent parallel lines on the graph.I drew the parallel lines and found out the intersection points of the parallel lines.As a result I get a rectangle and thus found out the area.
Now,my confusion is that one may interpret this as plotting the points $(3,0),(-3,0),(0,5),(0,-5)$ and joining them and finding the area of the figure so formed.
So,which is correct?
Your statement
is wrong.
The points are the intersections of the given lines, so they are: $(3,5),(-3,5), (-3,-5), (3,-5)$.