Let $X = \mathbb{R}$ equipped with usual topology $\tau$, then $\tau = 2^\mathbb{R}$
Does this imply that the cardinality of $\tau$ is greater than continuum?
Let $X = \mathbb{R}$ equipped with usual topology $\tau$, then $\tau = 2^\mathbb{R}$
Does this imply that the cardinality of $\tau$ is greater than continuum?
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