binomial(n, k) x^(n-k) y^k
Given newtons binomial theorem.
I believe the answer is
n = 25 k = 16
binomial(25, 16) 7^(9) 21^16
2026-04-04 03:56:45.1775275005
What is the coefficient of x^9 y^16 in the expansion of (7x+21y)^25
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Yes true. By binomial theorem we have
$$(7x+21y)^{25}=\sum_{k=0}^{25}{25\choose k}(7x)^k(21y)^{25-k}$$ so for $k=9$ the term is $${25\choose 9}7^9\times (21)^{16} x^9 y^{16}$$