What is the condition to split integral in Lebesgue theory?

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Let $f:[0,1]^2\rightarrow \Bbb R$ be defined by

$$f(x,y)=1/y^2 \text{ if }0\leq x <y<1$$ $$f(x,y)=-1/x^2\text{ if }0\leq y <x \leq 1$$ $$f(x,y)=0 \text{ otherwise}$$ If can show that $$\int_{0}^{1}\int_{0}^{1}f(x,y)dxdy \neq \int_{0}^{1}\int_{0}^{1}f(x,y)dydx$$ In my course, it is written that the last equation does not contradict fubini's theorem since $\mid f\mid$ is not integrable on $[0,1]^2$. I don't know why and I can't compute the integral of $\mid f \mid$ on $[0,1]^2$. Any help would be appreciated

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By Tonelli's Theorem $\int |f| \geq \int_0^{1}\int_x^{1}\frac 1 {y^{2}} dydx=\int_0^{1}(\frac 1 x-1) dx =\infty$.