For a given commutative algebra $A$ over a field $\mathbb{K}$(with char=0) the algebra of differential operators on $A$ is the set of endomorphism $D$ of $A$ such for some $n$ we have that for any sequence $\left\lbrace a_i\right\rbrace_{1\leq i\leq n}$ for $a_i\in A$ one has $[\ldots[[D,a_0],a_1],\ldots,a_n]=0$.
By analogy, I think of Hochschild Cohomology as a sort of "algebraic differential forms"(maybe this isn't the right approach, but $C^{n}(A,A)=Hom(A^{\otimes n},A)$ and it gives a cohomology theory etc.), thus it seems like there should be a connection to differential operators on the algebra.
Sorry if the question is a little general, but I am open to accepting a variety of answers.
Thanks in advance!
The usual way to relate Hochschild (co)homology of a commutative algebra to "differential-geometric" concepts is the Hochschild-Kostant-Rosenberg theorem: if A is a smooth commutative k-algebra, there exists a (graded) isomorphism $\Omega^\bullet A\to HH_\bullet(A,A)$ (see e.g. theorem 3.4.4 in Loday's Cyclic homology book or the nLab entry and links there).
Now, I don't know about any direct connection to differential operators. But there is a general way to get differential operators from differential forms: to apply (relative) Koszul duality to de Rham complex (it's described... well, e.g. in Positselski's "Two kinds of derived categories...", although it's an overkill, perhaps; see also "What is Koszul duality?").
Hope, it helps.