What is the cycle index for the Dihedral Group acting on a hexagon?
So I believe the answer is:
$$
\frac{1}{12}(x_1^6 + 2x_6^1 + 2x_3^3 + 4x_2^3 + 3x_2^1x_2^2)
$$
but I'm not sure if I may have mixed up something. These things seem quite tedious!
2026-03-27 13:03:39.1774616619
What is the cycle index for the Dihedral Group acting on a hexagon?
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I think you're not quite right, so let me try and go through the elements one at a time. If I have this correct $x_n^m$ means there are $m$ cycles of order $n$. Let me know if you think one of these is incorrect, and I'll try and explain my reasoning.
id=$x_1^6$
$f$ contributes to $x_2^2x_1^2$
$r,r^{-1}$ both equal $x_6^1$
$r^2,r^{-2}$ both equal $x_3^2$
$r^3,r^3f,rf,r^{-1}f$ contribute to $x_2^3$
$r^2f,r^{-2}f$ both equal $x_2^2x_2^1$
so in total $x_1^6+4x_2^3+2x_6^1+2x_3^2+3x_2^2x_1^2$