Given the value $690$, I want to remove $10$% from that and then remove another $20$% from the resulting value, so as an example, I am doing:
$690 \over {(1 + 0.1 + 0.2})$ = $690 \over {1.3}$ = $530.76.$ Apparently, I was told this is wrong and it should be:
$690 * 0.9 =$ $621 \over {1.2}$ = $517.50$
In the above, the $10$% is non-compounded and the $20$% is compounded. Can someone explain what is the difference between the $2$ and is one way better than the other if I do not know certain values like the start or end value (690 in this case)
If I do $690 \over {1 + 0.111111111111 + 0.2}$, I get closer to $517.50.$
If you remove $10\%$ from $690$, your new value is $690-690\cdot \frac{10}{100}$. This is $690\left(1-\frac{10}{100}\right)$, or more simply $(690)(0.9)$.
To remove $20\%$ from the new value of $(690)(0.9)$, you go through essentially the same process, and arrive at $(690)(0.9)(0.8)$.
Note that we would have gotten to the same final answer if we removed $20\%$ from $690$, and then removed $10\%$ from the result.
I do not know what you mean by "if I do not know certain values." If we only know the percentages removed, we cannot know the dollar amounts.
But if the initial price is $A$, and you remove $10\%$ and then $20\%$, the same reasoning leads to the final price of $A(0.9)(0.8)$.
So if you know that discounts of $10\%$ and then $20\%$ were applied, and the final price was, say, $576$, then you can determine the original price as follows. Let $A$ be the original price. Then $$A(0.9)(0.8)=576,$$ and therefore $$A=\frac{576}{(0.9)(0.8)}.$$