A parabola has the equation:
$$x + (y - 2)^2 = 0$$
I can't find the $y$ without getting the equation into some weird recursion.
A parabola has the equation:
$$x + (y - 2)^2 = 0$$
I can't find the $y$ without getting the equation into some weird recursion.
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We need to solve for $y$ and take the negative branch.
We write $x + (y - 2)^2 = 0 \Rightarrow y=2\pm(-x)^{1/2}$.
Thus, the bottom half of the parabola is $y=2-\sqrt{-x}$ in terms of $x$.