I am trying to plot the following curve. It has 3 leaves, each leaf is identical and 120 degrees apart. It is traced as shown in the attached numbers.
My attempt is $r(\theta)=1-0.6\sin(3\theta)$ but I have no idea how to adjust it to resemble the curve above.
\documentclass[pstricks]{standalone}
\usepackage{pst-plot}
\begin{document}
\begin{pspicture}[showgrid](-3,-3)(3,3)
\psplot[algebraic,polarplot,linecolor=red,plotpoints=100]{0}{Pi 2 mul}{1-.6*sin(3*x)}
\end{pspicture}
\end{document}
Question
What is the equation of the polar curve or parametric curve (or any kind of curve) given above?



Probably not what you are looking for, but, with $$f(t) = \frac{1}{3}t+\frac{3}{2}\cos\left(\frac{1}{2}t\right)-\frac{1}{5}\sin t,$$ the curve $$ x(t)=\int_{0}^t \cos(f(u)) \, du, \,\, y(t) = \int_{0}^t \sin(f(u)) \, du $$ looks like this:
which looks like your curve if you squint.
UPDATE: With $$f(t) = \frac{1}{3}t+\cos\left(\frac{1}{2}t\right)-\frac{1}{5}\sin t,$$ the curve is this: