What is the inverse Laplace Transformation of F(s)*G(s) utilizing convolution theorem?

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I have learnt about the Laplace convolution theorem: $$\mathcal{L}[f(t)*g(t)]=\mathcal{L}[f(t)]\mathcal{L}[g(t)]$$ So I wonder if there any solution to $$\mathcal{L^{-1}}[F(s)*G(s)]=?$$ If there isn't, why there is in Fourier Transformation?