Given $\epsilon >0$, what is the largest $\delta >0$ which fits the definition of continuity of the function
$$f(x)=\begin{cases} \frac{x+3}{2},& \text{if } x \leq 1\\ \frac{7-x}{3}, &\text{if } x\geq 1\\ \end{cases}$$
at $x=1.$
I try to find out $\vert f(x)-f(1)\vert < \epsilon$ for two different cases but I get nothing. Please help.
For $x<1$: $|f(x)-f(1)|=|\frac{x+3}{2}-2|=\frac{1}{2}|x-1|$
and
for $x<1$: $|f(x)-f(1)|=|\frac{7-x}{3}-2|=\frac{1}{3}|x-1|$.
Can you proceed ?