I'm rather new at this so please try to make it simple.
Reading the wikipedia's adjunction Definition via counit–unit in the following link: https://en.wikipedia.org/wiki/Adjoint_functors#Definition_via_counit%E2%80%93unit_adjunction, I came across the symbol $F\eta$, where $\eta:1_{\cal D}\rightarrow GF$ and $F:\cal D\rightarrow\cal C$ and $G:\cal C\rightarrow \cal D$; $\eta$ is a natural transformation, $F,G$ are functors and $\cal C, \cal D$ are categories.
This is probably a silly question but what does $F\eta$ represents? is it $F\circ\eta$?
In that case, how does it work? in the diagram it says: $F\eta(F)\rightarrow FGF$, but $\eta$'s domain does not contain $F$..
Clarification would be much appreciated.
First, notice that Wikipedia has $F : \mathcal D \to \mathcal C$ and $G : \mathcal C \to \mathcal D$, rather than the other way around.
$F \eta : F \Rightarrow F G F$ is the whiskering of $\eta$ with $F$. This is described in the last two paragraphs here. Whiskering can be seen as a special case of composition of natural transformations, if we identify the functor $F$ with the identity natural transformation on $F$.
Recall that $\eta$ is a family of morphisms $\eta_D : D \to GF(D)$. $F \eta$ is then a natural transformation constructed from $F$ and $\eta$, defined by $(F\eta)_D = F(\eta_D) : F(D) \to FGF(D)$.
There is an analogous whiskering $\epsilon F : F G F \Rightarrow F$, of $F$ with $\epsilon$, given by $(\epsilon F)_D = \epsilon_{F(D)} : FGF(D) \to F(D)$. Similarly, we can whisker $G$ with both natural transformations as well.