In this context, $\mid$ is a relation: $m \mid n$ means that $m$ divides $n$, or equivalently $n$ is a multiple of $m$. This means that there is an integer $\ell$ such that
$$ n = \ell m.$$
If $m$ and $n$ are positive integers with $m \mid n$, then we must have $m \le n$. The symbol "$\mid$" is read divides and is produced by \mid in $\LaTeX$.
Therefore the proposition in the article, "if $n \in \mathbb{N}$, then $12 \mid (n^4 - n^2)$", simply means that $n^4 - n^2$ is divisible by $12$ for each natural number $n$.
However note that the notation in the article is somewhat abusive in that, for instance
$12 \mid (1^4 - 1^2) = 12 \mid (1- 1) = 0 = 0*12$
should instead be something like
$12 \mid (1^4 - 1^2) \iff 12 \mid (1- 1) \iff 12 \mid 0$, which is true since $\overbrace{0}^n = \overbrace{0}^\ell \times \overbrace{12}^m$ (or since $0$ is a multiple of $12$).
3
Bumbble Comm
On
In the C programming language, it means the bitwise "or" function. Write your numbers in base 2, and then "or" each corresponding digit.
In this context, $\mid$ is a relation: $m \mid n$ means that $m$ divides $n$, or equivalently $n$ is a multiple of $m$. This means that there is an integer $\ell$ such that
$$ n = \ell m.$$
If $m$ and $n$ are positive integers with $m \mid n$, then we must have $m \le n$. The symbol "$\mid$" is read divides and is produced by
\midin $\LaTeX$.Therefore the proposition in the article, "if $n \in \mathbb{N}$, then $12 \mid (n^4 - n^2)$", simply means that $n^4 - n^2$ is divisible by $12$ for each natural number $n$.
However note that the notation in the article is somewhat abusive in that, for instance
should instead be something like