In triangle ABC, AB is larger than BC.
Then, we choose point E outside the triangle such that BE=BC.
We extend line AB to D, such that BD=BC.
BF is angle bisector of angle ABC.
If DC is parallel to BF, what is the measure of angle ECD?
In triangle ABC, AB is larger than BC.
Then, we choose point E outside the triangle such that BE=BC.
We extend line AB to D, such that BD=BC.
BF is angle bisector of angle ABC.
If DC is parallel to BF, what is the measure of angle ECD?
According to your drawing, the angle ECD is equal to the angle CBF, and the latter is half of the angle ABC.
All in all :
$$\hat{ECD}=\hat{ABC}/2$$
If you don't have any information on the angle ABC, then you wont find the angle ECD