This is because this function is not periodic. Suppose in fact that $(x + t) \sin(x + t) = x \sin(x)$ for $t > 0$. Then
$$
\forall n \in \mathbb N: \frac{\pi}{2} = \frac{\pi}{2} \sin\left( \frac{\pi}{2} \right) = \left(nt + \frac{\pi}{2}\right) \sin\left( nt + \frac{\pi}{2} \right).
$$
Yet either $t$ is a fractional multipl of $\pi$, leading to an immediate conradiction by preiodicity of $\sin$, or it is not, in which case the orbit of the action by $n$ is dense in the values o $\sin$ (as the corresponding dynamical system is minimal), leading to another contradiction.
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Bumbble Comm
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Since $f(x) = x\sin x$ has $f((2n + \frac{1}{2})\pi) = (2n + \frac{1}{2})\pi$ for any integer $n$, it is unbounded and thus not periodic.
This is because this function is not periodic. Suppose in fact that $(x + t) \sin(x + t) = x \sin(x)$ for $t > 0$. Then $$ \forall n \in \mathbb N: \frac{\pi}{2} = \frac{\pi}{2} \sin\left( \frac{\pi}{2} \right) = \left(nt + \frac{\pi}{2}\right) \sin\left( nt + \frac{\pi}{2} \right). $$ Yet either $t$ is a fractional multipl of $\pi$, leading to an immediate conradiction by preiodicity of $\sin$, or it is not, in which case the orbit of the action by $n$ is dense in the values o $\sin$ (as the corresponding dynamical system is minimal), leading to another contradiction.