What is the property that allow the transformation $\frac{16a^3}{8ac}=\frac{16}8\cdot\frac{a^3}a\cdot\frac1c$?

Question

In a monomial division like this: $$\frac{16a^3}{8ac}=\frac{16}8\cdot\frac{a^3}a\cdot\frac1c$$ Why I can do this $\dfrac1c$? Where this 1 come from?

Answer 1

Well, I would say that it's because $c^0=1$ hence, you've got : $$\frac{16a^3}{8ac}=\frac{16a^3c^0}{8ac} =\frac{16}{8}\cdot\frac{a^3}{a}\cdot\frac{c^0}{c} =\frac{16}{8}\cdot\frac{a^3}{a}\cdot\frac{1}{c}$$

Answer 2

Because 1 is the unity for multiplication/division.

(And I think there is a typo in the question)