At the end of chapter 5 of stein's book A Computational Introduction to Algebraic Number Theory he proves proposition 5.2.4 which states that:
Given a prime ideal $\mathfrak{p}$ in a Dedekind domain $R$ we have the isomorphism $$ \frac{\mathfrak{p}^n}{\mathfrak{p}^{n+1}} \cong \frac{R}{\mathfrak{p}} $$ of $R$-modules for any $n \geq 0$.
What is the point of including this proposition, other than the fact it can be proved using the Chinese Remainder Theorem? I don't see why this is important.
It's used, for example, to show that the ideal norm is multiplicative. This is Prop 6.3.4 in Stein's notes.
For a number field $K$, for each non-zero ideal $\mathfrak a\subset\mathcal O_K$, we define it's norm to be $$N(\mathfrak a)=\#(\mathcal O_K/\mathfrak a).$$ It's clear from the Chinese remainder theorem that $$N(\mathfrak {ab}) = N(\mathfrak a)N(\mathfrak b)$$ if $\mathfrak {a,b}$ are coprime, so to show $N$ is multiplicative, all that remains is to show that $$N(\mathfrak p^n) = N(\mathfrak p)^n$$ for any prime ideal $\mathfrak p$. The map $$\mathcal O_K/\mathfrak p^{n+1}\to\mathcal O_K/\mathfrak p^{n}$$ has kernel $\mathfrak p^n/\mathfrak p^{n+1}$, which is isomorphic to $\mathcal O_K/\mathfrak p$ by the proposition. Hence, $$N(\mathfrak p)N(\mathfrak p^n) = N(\mathfrak p^{n+1}),$$ and the result follows by induction.