What is the region of convergence of $x_n=\left(\frac{x_{n-1}}{n}\right)^2-a$, where $a$ is a constant?

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The following recurrence relation came up in some research I was working on:

$$x_n=\left(\frac{x_{n-1}}{n}\right)^2-a$$

Or equivalently the map:

$$z\mapsto\frac{z^2}{n^2}-a$$

Where $n$ is the iteration number. Specifically, I'm interested in the size of the convergence region across the real line. Some stuff I know about this map:

  • For $a = 1$, it's easy, the "size on the real line" is $[-3,3]$.

I do have an infinite radical expansion for the size of the convergence region on the real line (see Solving the infinite radical $\sqrt{6+\sqrt{6+2\sqrt{6+3\sqrt{6+...}}}}$):

$$\sqrt{a+2\sqrt{a+3\sqrt{a+...}}}$$

That's why it's easy for $a=1$ -- it's just the Ramanujan radical, and equals 3. It's also easy for $a=0$ -- it's $\exp\left(-\mathrm{PolyLog}^{(1,0)}(0,1/2)\right)$ as per Wolfram Alpha.

Has anyone seen this map before? Here's the region of convergence on the complex plane, plotted numerically (for $a=6$):

enter image description here

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Reminded me of this particular Julia set. It's the one generated from the Mandelbrot set's (0,0) point. Picture

Mandelbrot set on the left, Julia on the right.