For the first part of part (b) I get the result by using a similarity transformation $ x=Rx^{*}$ but I am not sure how to go about the relation between their eigenvectors.
Any help would be much appreciated!
For the first part of part (b) I get the result by using a similarity transformation $ x=Rx^{*}$ but I am not sure how to go about the relation between their eigenvectors.
Any help would be much appreciated!
If $v$ is an eigenvector of $B$, then $Rv$ is an eigenvector of $A$: if $\lambda\in\mathbb R$ is such that $Bv=\lambda v$, then$$Bv=\lambda v\iff R^{-1}ARv=\lambda v\iff A(Rv)=\lambda Rv.$$By a similar argument, if $w$ is an eigenvector of $A$, then $R^{-1}w$ is an eigenvector of $B$.