So, there is a definition in my book for the uniform convergence of a sequence of functions:
Let $E$ be a nonempty subset of $\mathbb{R}$. A sequence of functions $f_n:E\to\mathbb{R}$ is said to converge uniformly on $E$ to a function $f$ if and only if for every $\epsilon$ there is an $N \in \mathbb{N}$ such that $n \ge N$ implies $|f_n(x) - f(x)| < \epsilon$ for all $x \in E$.
Now, the definition for the Uniform Cauchy Criterion is essentially the same, except that it states:
... Then $f_n$ converges uniformly on $E$ if and only if for every $\epsilon > 0$ there is an $N \in \mathbb{N}$ such that $n, m \ge N$ implies $|f_n(x)-f_m(x)| < \epsilon$ for all $x \in E$.
What is the signifance of this? What is so important about there being an $m \ge N$ such that $|f_n(x) - f_m(x)| < \epsilon$?
My book doesn't touch on this for some reason.
Let $X$ be a set endowed with a metric $d$. A sequence $(x_n)_{n\in\mathbb{N}}$ is convergent to $x\in X$ with respect to the metric $d$ if for every $\epsilon>0$ there exists an $N\in \mathbb{N}$ such that for all $n>N$, $d(x_n,x)<\epsilon$. Similarly, the sequence is called Cauchy if for every $\epsilon>0$ there exists an $N\in\mathbb{N}$ such that $n,m>N\implies d(x_n,x_m)<\epsilon$. In your case, $X$ is some set of functions from $E\to \mathbb{R}$, and the metric used is the sup-metric: $d(f,g)=\sup_{x\in E} |f(x)-g(x)|$. For any metric space, every converging sequence is Cauchy. However the converse does not always hold. Metric spaces for which this does, (i.e. spaces in which every Cauchy sequence is convergent) are called complete. If we assume in your case, that we work with all bounded functions from $E$ to $\mathbb{R}$, then this space is in fact complete, hence the two notions are equivalent. Beware, however, that this does not always hold for some more "unnatural" function spaces.