What is the Taylor Expansion of a function

Question

What is the Taylor expansion of the function $$G(x)=\frac{1}{(1-x^{50})(1-x^{25})(1-x^{10})(1-x^5)(1-x)}\quad ?$$

Answer 1

Because $\dfrac{1}{1-x}=\sum{x^n}$ , $n\ge0$ $$G(x)=(\sum{x^n})(\sum{x^{5n}})(\sum{x^{10n}})(\sum{x^{25n}})(\sum{x^{50n}})$$